Cu(OH)2(s) dissolves in excess aqueous ammonia with the formation of Cu(NH3)42+(aq)
What is the net ionic equation?
i) Cu(OH)2(s) --> Cu2+(aq) + 2OH-(aq)
ii) Cu(OH)2(s) + 4NH3(aq) --> Cu(NH3)4 2+(aq) + 2OH-(aq)
iii) Cu(OH)2(s) + 4NH3(aq) + 2H3O+(aq) --> Cu(NH3)42+ (aq) + 4H2O(l)
I'm not the greatest at this whole balancing thing yet - still need a little bit of practice
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Topic: Complex Net-Ionic Equation (Read 10781 times)