1) how many moles of h2 gas should be taken up by 1 octene in the courseof this reaction?
CH3-(CH2)5-CH=CH2 -> (H2PtCl6) -> NaBH4, C2H5OH, HCL -> CH3-(CH2)5-CH2-CH3
Answer is 2 right???
2) What volume does this correspond to at STP?
How can i solve this part?
3) how many moles of molecular hydrogen are consumed per mole of the precatalyst (H2PtCl6) in order to convert it enterily to platinum metal?
Isnt this 2 also?? what is the diff between this and the moles of H2 gas for the question #1?
4) How many moles of precataylst (H2PtCl6) are used in this reaction?
Again is isn't this 2??
My answers don't seem right and i am still a little dubios before submitting them...am i misunderstanding a simple concept here?
thanks