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Topic: Calculating Weight (Read 3430 times)
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biz
New Member
Posts: 4
Mole Snacks: +0/-0
Calculating Weight
«
on:
October 21, 2007, 07:29:48 PM »
I really need help with this question. Ugh.
It's all about unit cancellation but I just can't seem to work it out! Please help.
"Calculate the weight of Na
2
S
2
O
3
x 5H
2
O to prepare 400mL of a solution of ~4.0x10
-2
M S
2
O
3
2-
"
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agrobert
Chemist
Full Member
Posts: 629
Mole Snacks: +69/-17
Gender:
diels alder
Re: Calculating Weight
«
Reply #1 on:
October 21, 2007, 07:36:05 PM »
Cancel Molarity units multiplying by total volume. As M = [x mol]/[1L]. So you need to convert 400-ml to L. Then you have required mol needed so cancel out with the MW to get your answer in grams. Remember one mol of Na
2
S
2
O
3
x5H
2
O gives 1 mol of S
2
O
3
-2
.
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In the realm of scientific observation, luck is only granted to those who are prepared. -Louis Pasteur
biz
New Member
Posts: 4
Mole Snacks: +0/-0
Re: Calculating Weight
«
Reply #2 on:
October 21, 2007, 07:49:28 PM »
Here's what I did:
4.0 x 10
-2
mol x 0.4 L = 0.016 mol
------------------------- -------
L 1
So then, 0.016 mol x the molar mass of Na
2
S
2
O
3
x 5H
2
O? Is that right?
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biz
New Member
Posts: 4
Mole Snacks: +0/-0
Re: Calculating Weight
«
Reply #3 on:
October 21, 2007, 07:58:16 PM »
Ok, yeah. I got it! Thanks for your help.
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