[ethan]

okay I found that:

29.33% Co(2+)
8.68% C2O4(2-)
61.99% H2O

Synthesis Equation:

aCoCl2 * 6H2O + bH2C2O4 + cH2O ---> Coa(C2O4)b * cH2O + H + Cl

I need to find the values of a,b,c

With the percents I found ratios:

7H2O=1C2O4
2H2O= 1CO
7Co=2C2O4

So then I got:

14CoCl2 * 6H2O + 4H2C2O4 + 28 H2O ----> Co14(C2O4)4 * 28 H2O + 76H + 28Cl

The equation doesnt balance though...And I just have a feeling that I did the ratios wrong. Can someone please help?

[Borek]

Ratios are wrong. What should be cobalt oxalate formula if you use just charges of both ions?

[ethan]

Okay, so a=b

but then how do you find out c if the ratios are different

[Borek]

okay I found that:

29.33% Co(2+)
8.68% C2O4(2-)
61.99% H2O

I understand that's mass percentage? Where did you get it from?

[ethan]

We had to mass everything after we heated it and everything. Im positive I have the right method for obtaining the mass of all the residue and conversions for finding the percents. I just dont understand how to find the values of a,b,c.

[Borek]

1:7 ratio you have found suggests that you have used correct approach, as it seems it is incorrect - there must be IMHO something wrong with the data you have listed.

[AWK]

CoC2O4 should contain much (1.424 times) more C2O4^2- anion than Co²⁺ cation - namely 41.76 %. Otherwise this analysiss is wrong.

[ethan]

Well its based on the experiment that we performed in class. So those are my results. The reactants side should have +2H2O added to it. ( The teacher gave us the wrong formula)

[Borek]

Please post your raw data.