Hey folks
I'm a pretty smart guy, but this question has left me second guessing myself. Second guessing myself so much that I've come here for help.
Click the thumbnail to see the question the question.
But...from what I gather using degree of saturation, measuring the height of each HNMR peaks(mm ratio provides proton ratio), plus knowing that there are 9 different carbons
My answer is a meta-substituted aromatic ring with NH2 on one side, and CH2CH2-OCO(ester, with the Oxygen linked with the CH2 group)-N(CH2)2-and the 2 CH2's linked with a CH3.
So basically it looks like procainewith the ester and the 2 CH2 groups switched around.
Any help would be very much appreciated.