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Topic: Ionization of a weak acid.  (Read 7453 times)

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Offline galaxy13

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Ionization of a weak acid.
« on: November 21, 2007, 09:44:12 AM »
The % ionization of a weak acid always declines in a solution that contains the salt of the anion, relative to a solution of the acid alone. For example, the % dissociation of acetic acid is less in a solution that contains sodium acetate than if the acetic acid were alone. Verify this for a 0.5 M solution of acetic acid and 0.5 M each acetic acid/acetate, and explain why.

Offline Borek

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Re: Ionization of a weak acid.
« Reply #1 on: November 21, 2007, 10:22:26 AM »
Please read forum rules.
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Offline AWK

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Re: Ionization of a weak acid.
« Reply #2 on: November 21, 2007, 10:23:18 AM »
Just calculate degree of dissociation for both solution and compare results
AWK

Offline galaxy13

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Re: Ionization of a weak acid.
« Reply #3 on: November 21, 2007, 11:51:20 AM »

Offline Borek

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Re: Ionization of a weak acid.
« Reply #4 on: November 21, 2007, 12:27:37 PM »
Quote
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Offline galaxy13

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Re: Ionization of a weak acid.
« Reply #5 on: November 22, 2007, 02:41:37 AM »
I suppose I have to write two equations, one for each of the solutions. But I can't understand how these equations are different.

Offline AWK

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Re: Ionization of a weak acid.
« Reply #6 on: November 22, 2007, 04:36:40 AM »
for the acid degree of dissocistion is SQRT(K/c) (c of acid)
for the buffer -  K/c (c of salt)
You have the same both: c of acid and c of salt

These are quite different equations
AWK

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