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Topic: Equilibrium Potential of Half Cell  (Read 4807 times)

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Offline DUDE778

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Equilibrium Potential of Half Cell
« on: November 19, 2007, 08:46:55 PM »
 Ce4+ + e− --> Ce3+    E° = 1.72 V   
 Fe3+ + e− -> Fe2+    E° = 0.771 V   

What volume of 0.76 M Ce4+ solution must be mixed with 32 mL of 0.30 M Fe2+ solution to produce a solution which produces a platinum electrode potential (relative to SHE) of 1.2455 V.

Am i using the nernst equation?  If so, how would i got around doing it.  If not, then what am i doing :S

Offline Borek

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Re: Equilibrium Potential of Half Cell
« Reply #1 on: November 20, 2007, 02:44:06 AM »
Nernst equation will give you ratio of Ce4+/Ce3+ (or Fe3+/Fe2+), then it is simple stoichiometry.
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