[d.mahmoud]

hi,
i need help to understand oxidation of ketones
either by
1- KMNO4
2-Beyer villiger
and wat is the product in each case , please
thanks

[smellor]

if you read the forum rules it seems that people are unlikely to give you any response unless you show at least an attempt at solving this problem yourself. additionally, most decent textbooks should cover this to some extent...

[Nick.Sparrow]

about Baeyer-Villiger oxidation, see

http://www.organische-chemie.ch/index3.htm?http://www.organische-chemie.ch/OC/Namen/Baeyer-Villiger.htm

In the case of KMnO4, the reaction is selective only in the cases when one of the radicals R can not be oxidated, otherwise you will heve to different acids from one Ketone

[d.mahmoud]

hi
thank you for reply
i really appreciate it
but my problem is that i have seen in a book that oxidation of ketones by kmno4
give 2 molecules of carboxylic acid but i could not understand how did they formed
if some one can help me in this, i will be so gratefull
thanks,,

[puppy8800]

C-C bonds break, forming carboxylic acids respectively
if an asymmetric ketone is oxidized by KMnO₄(H⁺), either C-C bond could break, and the product is usually a mixture of acids

[agrobert]

As in  Nick.Sparrows example, the lower reaction is an asymmetric ketone that breaks a C-C bond to make acetic acid without selectivity also yielding propanoic acid.