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Topic: specific heat of metal dropped in water  (Read 2775 times)

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Offline rodger

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specific heat of metal dropped in water
« on: December 09, 2007, 01:28:14 PM »
a 35 g block of metal at 80 degree celcius is added to a mix of 100 g water and 15 g ice in an insulated container. All of the ice melts and the temperature in the container rose to to 10 degree celcius. what is the specific heat of the metal??

it is given that the specific heat of water is 4.184 J
and that the latent heat of fusion is 333 J

i think that i should be using the equation q=(m) (c) (change in T) and set the initial equal to the final, but i am still having some trouble. Thanks

Offline Yggdrasil

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Re: specific heat of metal dropped in water
« Reply #1 on: December 09, 2007, 02:05:43 PM »
You also need to take into account that some of the heat from the metal melts the ice.  To figure out how much heat is needed to melt the ice, use the equation q = mL where L is the latent heat of ice.

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