[helpmeimnoob]

ok, once again, i need help with another phase change problem:

what is the amount of energy that must be removed from 125.0 grams of water @ 35.7 degrees C when converted to ice @ 0.0 degrees C?

Ok, so I got this far:

4.18J/1g x deg C     X    125g    X 35.7 deg C = 18653.25

Then...

(something i dont know)/(something i dont know) x 125g = (something I dont know)

Can someone plugg the items in?

[Sev]

L_f of water is 334Jg^-1.  So how much energy to convert 125g of water (at 0⁰C) to ice?

[Alpha-Omega]

This is called Latent Heat:

•   Energy = mass X latent heat of fusion


You have everything you need Sev gave you the Latent Heat for water.