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Topic: ppm  (Read 3267 times)

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Offline FeRocks

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ppm
« on: January 10, 2008, 12:47:11 AM »
Prepare 1 L of a solution containing 1.0 ppm Fe+2. How many grams Ferrous ammonium sulfate, FeS04*(NH4)2S04*6H2O, must be dissolved and diluted in 1 L? What would be the molarity of this solution? So confusing with the ppm. Help please. thanks.
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Offline Alpha-Omega

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Re: ppm
« Reply #1 on: January 10, 2008, 01:08:46 AM »
Step1:  Calculate the Fwt of the hexahydrate.

1 ppm solution is 1 ppm = 10^6 (million) or 1 mg/ 1 kg solution (1 liter) or 1 mg/L

1M = gfw X/L

Step 2:  Then set up your conversion

gfw FeS04*(NH4)2S04*6H2O/1 Mole x 1 Mole Fe2+/1Mole FeS04*(NH4)2S04*6H2O x think you can figure it out from there???
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