I have reconcidered it. Does a concentration of 2.80 x 10
-5 M seem a better answer for a) ?
For b) I'm not sure. This is what I've done:
From the stoichiometric ratio, [CrO
42-] = 0.5[Ag
+].
In the solution then
[CrO
42-] = 0.5 [Ag
+] + 0.005 M (from potassium dichromate)
Assume the dissociation of potassium dichromate surpresses the solubility of silver dichromate, so that [CrO
4] = 0.005.
In other words 0.5[Ag
+] << 0.005.
[Ag
+]
2 (0.005) = 1.1 x 10
-11Therefore [Ag
+] = 4.69 x 10
-5 M
i.e. 4.69 x 10
-6 M in 100 mL.
OR should the final answer be 4.69 x 10
-4 M in 100 mL. Should I multiply or divide by ten? I'm confused.
Another thing that I'm not sure about is whether I should use the the "20g" given or not. With the exam paper there wasn't any periodic table or molar mass indicated, and it's not as if I memorize elements' molar mass to four decimal places.