Ok, I tried this different approach; I abandoned the ICE table as well. Here is what I did:
For Step 1) Calculated the # of moles of acetic acid. I got 0.002mol. Then I divided that by 0.04L (which is 40ml converted to litres) to get 0.05mol/L
For Step 2) I did the same thing by using M1V1=M2V2 to get 0.05mol/L
For Step 3)Then I added 0.05mol/L with 0.05mol/L to get 0.1mol/L. Then I assumed 1L and multiplied that by 0.1mol/L (to cancel out the Litres).
Finally, divided 0.1mol/ by 0.08L (which is 80ml converted to litres) to get a final answer of 1.25mol/L
I'm fairly certain this is incorrect but I gave it yet another shot. Any feedback would be greatly appreciated. Thanks in advance.