Please check and correct if it's wrong. Thank you.
Sulfur and oxygen react in a combination reaction to produce sulfur trioxide, an environmental pollutant: 2S+3O2=2SO3. In a particular experiment, the reaction of 1.0 g S with 1.0 g O2 produced 0.80 g of SO3. The % yield in this experiment is………
My Solution:
1g S=3.119 x 10^-2 mol S
1 g O2=3.125 x 10^-2 mol O2
O2 limiting
mole-to-mole
3.125 x 10^-2 mol O2=2.08 x 10^-2 mol SO3 = 1.67g SO3
0.80/1.67 x 100%=47.9%
Is this correct? Thank you.