At 250 degrees Celsius the reaction below has an equilibrium constant Kc of 1.80.
PCl5(g) <--> PCl3(g) +Cl2(g)
If .153 mol PCl5 is added to a 5.00L vessel, what are the concentrations of all reactants and products in the equilibrium mixture at this temperature?
So for the M of PCl5, I think you would just figure out the M for 1 L, since you have .153 for 5L? But I'm not sure.