Are you asking why sulphur reacts with the diatomic oxygen molecule to form covalent product, but not react with oxygen radical? If this is what you are asking, I can tell you is that forming the O=O bond is more thermodynamically favoured than S-O or S=O bonds because being small and the same size, the degree of overlap of the O valence orbitals would be greater, and thus stronger bond, and hence more exothermic than forming the sulphur-oxygen bonds. Hence, the oxygen radicals are more likely to react with each other before reacting with sulphur.