[Noor]

Starting with 0.4900 mol CO(g) and 0.0400 mol COCl2(g) in a 1.000 -L flask at 668 K, how many moles of Cl2(g) will be present at equilibrium?

CO ( g) + Cl2 (g) ---> CoCl2 (g)

Kc= 1.2 x 10 ^3  at 668 K

I've tried this problem so many times yet the answer I always got was wrong.

I used the ICE table and came up with 0.1683 moles of Cl2 which is WRONGG!!! how do I do this?

[Noor]

*Ignore me, I am impatient*!!!!!

[AWK]

REad forum rules.
Show your work!
Concentration of Cl2 is practically null (without calculations - why?).