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Topic: Molar Enthalpy  (Read 4662 times)

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Offline Frederick95

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Molar Enthalpy
« on: March 13, 2008, 05:34:03 PM »
Why was my answer incorrect?




Question:
Try this question to see if you can use standard enthalpies to determine the molar enthalpy for the reactions given. Your answer must be in kiloJoules and accurate to 0 decimal places unless specified.

Find the molar enthalpy of a reaction with:
Solid calcium oxide and liquid water producing solid calcium hydroxide.Answer accurate to 1 decimal place


My answer:
CaO(s) + H2O(l) produces Ca(OH)2
38.1       69.95               83.4

69.95 (J /(mol x k)) / 1000 = 0.06995
38.1 (J /(mol x k)) / 1000 =0.0381
83.4 (J /(mol x k)) / 1000 = 0.0834

∆H = ∑n∆H°f(prod.) - ∑n∆H°f(react.)

     =.0834 - (.06995 + 0.0381)

     = .0834 - 0.10805

     = -0.02

     = -0.0 kJ /mol

Offline Borek

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Re: Molar Enthalpy
« Reply #1 on: March 13, 2008, 05:48:07 PM »
Are you sure entalpies were not already in kJ?
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Offline Frederick95

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Re: Molar Enthalpy
« Reply #2 on: March 13, 2008, 06:11:56 PM »
Borek,

I used standard enthalpies  which were given in J /mol

Offline Borek

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Re: Molar Enthalpy
« Reply #3 on: March 13, 2008, 06:32:40 PM »
Where did you get them from?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Frederick95

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Re: Molar Enthalpy
« Reply #4 on: March 13, 2008, 06:51:05 PM »
A chart entitled Molar Enthalpies and Enthalpies of formation(which doesnt want to send)

Offline Borek

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Re: Molar Enthalpy
« Reply #5 on: March 13, 2008, 07:10:52 PM »
You either don't understand it or misread its content. Values you have listed have nothing to do with molar enthalpies of these subtances.
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Offline Frederick95

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Re: Molar Enthalpy
« Reply #6 on: March 13, 2008, 07:25:32 PM »
In that case, I will talk with my teacher about it ;)

Borek, I was wondering if you can help both me and Marcus regarding his earlier question about PV =nRT (we are in the same class together). I am stuck on the exact last question he has asked.

May god Bless you ;)

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