Topic: What's the mol of electron (Read 3723 times)

trinhn812 · « **on:** March 23, 2008, 05:01:58 PM »

When enough NaCl(s) is added to the compartment containing gold to make the [Cl–] = 0.10 M, the cell potential is observed to be 0.31 V. Assuming that the reaction in the gold compartment is
Au(3+)(aq) + 4Cl–(aq) --> AuCl4–(aq)
Calculate the value of K for this reaction at 25°C.

I think I'm hitting a chemistry brain freeze. Um can anyone tell me what "n" would be as in what is the number for the mol of electrons?

Borek · « **Reply #1 on:** March 23, 2008, 05:51:03 PM »

From the description you have Au/Au³⁺ electrode.

trinhn812 · « **Reply #2 on:** March 23, 2008, 06:47:07 PM »

oh so its 3 mols of electron. I'm planning on using nearnst equation.

Can anyone help me find what Q would be?

Q= [AuCl4-]/ [Au] [Cl]^4

I'm not sure waht the concentration would be

Borek · « **Reply #3 on:** March 23, 2008, 07:18:28 PM »

Write expression for K, solve for Au³⁺.

Write Nernst equation for Au/Au³⁺ electrode.

Put calculated Au³⁺ into Nernst equation.

Topic: What's the mol of electron (Read 3723 times)

trinhn812

What's the mol of electron

Borek

Re: What's the mol of electron

trinhn812

Re: What's the mol of electron

Borek

Re: What's the mol of electron

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