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3. The solubility product constant for Strontium Chromate is 3.6x10^-5. What is the solubility in g/100mLMW=204Ksp=[Sr][CrO4]=x^2x^2=3.6x10^-5 x=6x10^-3=Mg/L=(6x10^-3)(204)=1.224)(.1L)/(100mL)= 1.224x10^-4 g/100mL
(1.224g/L)(.1L/100mL)=1.22x10^-3