Hi all,
If given
N2: kH = 8.57×10^4 atm
O2: kH = 4.34×10^4 atm
How can I find the N2 to O2 equilibrium molar ratio knowing there's 78% N2 and 21% O2 in the air @ 25 degC?
I initially tried using ideal gas law equation
PV = nRT
n/V = P/RT
M= P/RT
then i solved for the individual partial pressures and plugged it into the ideal gas law equation to compare their molarities.
Apparently this was not the correct way of solving. Could anyone please shed some light on why this is the wrong approach and maybe lead me into the correct path?
Thanks