[Atome]

Hello everyone,

With the following problem, my answer was slightly different from the provided one. Could anyone please see if what the problem may be?

Thank you.

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1. The following reaction takes place in a sealed 40.0 L container at 120°C.

4NH₃ + 5O₂ --> 4NO + 6H₂O

                                           
When 34.0 g of NH3 react with 96.0 g O2, what will be the total pressure in the flask at the end of the reaction?

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34.0 g               96.0 g

= 2.00 mols        = 3.00 mols

Ammonia would be the limiting reagent.

Therefore:

                                                    = 2.00 mols x (10/4)
 
                                                    = 5.00 mols

After using P = (nRT)/V, I get 408 kPa. However, the answer is 449 kPa.

[Borek]

Products are not the only gases present after the reaction.

[Atome]

Thank you very much for your hint, Borek. I forgot to consider the excess reagent.