Alright, so. Did a little work on this but I'm not sure how to bring in the whole triangle aspect.
Using boundary conditions 1. vz(x, H) = 0 and 2. vz(x>=0, sqrt(3)*x) = 0 and vz(x<0, -sqrt(3)*x) = 0? Simplifying the navier stokes into dp/dz=u(d2vz/dy2). Now, before I get all crazy and start integrating I need to know where the triangle aspect comes in and where the (3x^2-y^2) comes into play and how.
Edit: Now that I look at this, I don't know if I can cancel out the d2vz/dx2, this would leave me with a 2nd order PDE which I did not believe my instructor would give us on this, although he did say "You do not need to solve for Vz, use answer given and show it satisfies a certain EQN."
Thanks again!
Update: Got to the PDE i've got he boundary conditions:
1. vz(x, H) = 0
2. vz(x>=0, sqrt(3)*x) = 0 and vz(x<0, -sqrt(3)*x) = 0
What am I missing...?
UPDATE:
Put everything together! Thanks guys!