December 23, 2024, 11:27:45 AM
Forum Rules: Read This Before Posting


Topic: Gas Involving Experiment  (Read 7399 times)

0 Members and 1 Guest are viewing this topic.

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Gas Involving Experiment
« on: May 03, 2008, 12:42:51 PM »
- Sorry but i had to delete my working out..


« Last Edit: May 08, 2008, 10:59:58 AM by Lilly »
Nothing is impossible because being impossible is possible.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Gas Involving Experiment
« Reply #1 on: May 03, 2008, 04:17:55 PM »
Does any one know how to set up the gas involving experiment for the chemistry planning exercise or where can i get more information on it?

30 seconds googling.

http://www.practicalchemistry.org/standard-techniques/generating-collecting-and-testing-gases,52,AR.html

Quote
Also i am using the Mg metal to react against the dibasic acid H2SO4.

Mg + H2SO4 --> MgSO4 + H2 We are given 1.00moldm of sulphuric acid.

What quantity of solid Mg do i use? How do i work it out?

This is my attempt:

Mg + H2SO4 --> MgSO4 + H2

Ratio of Mg to H2SO4 is 1:1

If i work out the moles of H2SO4 first by using 25cm of volume and concentratio is already given (1.00moldm) and i get 0.025. through this formula                 Moles=volume x concentration

so the moles for Mg are same 0.025 since the ratio is 1:1

and if i put the 0.025 into the formula Mass=moles x molar mass.. This is 0.025 x 24.3 = 0.6075g   <---- Is this a correct way?

Perfect approach, just remember you should use a little bit more Mg - you want it to be in excess, to be sure all acid reacted.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Re: Gas Involving Experiment
« Reply #2 on: May 04, 2008, 08:45:47 AM »
-
« Last Edit: May 08, 2008, 10:49:34 AM by Lilly »
Nothing is impossible because being impossible is possible.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Gas Involving Experiment
« Reply #3 on: May 04, 2008, 11:05:37 AM »
Mg + H2SO4 --> MgSO4 + H2 <--- Is this 2 moles?

What is stoichiometric coefficient? 1 or 2?

Quote
A dibasic acid should give me 2 moles of H+ ions.

The ratio for H2 to H2SO4 is 1:1

Do the same calculations for 1 mol of HCl and compare amount of H2 produced.

Quote
and i know that under typical laboratory conditions 1 mole of all gases occupy a molar volume of 24dm3 = 24000cm3

Not exactly. You should use PV=nRT, and to be really precise you should correct for water vapor pressure.

Quote
Ok i am confused..How do i work out how much H2 would be given out at the end? If it is too much and can not be measured-Is it ok to decrease by a scale factor?

Start with the volume you can meaure, than calculate amount of acid that should give this volume of gas, then calculate amount of Mg necessary.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Re: Gas Involving Experiment
« Reply #4 on: May 05, 2008, 01:00:27 PM »
Do you know what goes into the flask first the Mg granuales or the sulphuric acid?
Nothing is impossible because being impossible is possible.

Offline merkl

  • Regular Member
  • ***
  • Posts: 24
  • Mole Snacks: +2/-4
Re: Gas Involving Experiment
« Reply #5 on: May 05, 2008, 02:06:09 PM »
I would put the acid in first, then think up some way of adding the Mg without losing any gas given off when you put the bung on.

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Re: Gas Involving Experiment
« Reply #6 on: May 05, 2008, 03:00:39 PM »
-
« Last Edit: May 08, 2008, 10:49:55 AM by Lilly »
Nothing is impossible because being impossible is possible.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Gas Involving Experiment
« Reply #7 on: May 05, 2008, 03:46:45 PM »
- I intend to produce 600cm3 of H2 gas thats 0.6 dm

Sounds reasonable, although details may depend on the equipment available.

Quote
Molar volume 24dm3

Please remember - this is only approximation!

Quote
0.6075g

Pretty good mass to start with :)
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Re: Gas Involving Experiment
« Reply #8 on: May 05, 2008, 04:48:59 PM »
How much does magnesium has to be in excess?
Nothing is impossible because being impossible is possible.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Gas Involving Experiment
« Reply #9 on: May 05, 2008, 04:50:25 PM »
20% should do. You will see it was in excess - there should be visible piece of metal after the reaction.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Lilly

  • Regular Member
  • ***
  • Posts: 25
  • Mole Snacks: +2/-1
Re: Gas Involving Experiment
« Reply #10 on: May 05, 2008, 05:23:49 PM »
Thanx a million!

erm one last question.. for my titration experiment i decided to put the acid into the burette and NaOH in the conical flask. What indicator do i use for this? not sure but is it phenolphthalein?  :-\
Nothing is impossible because being impossible is possible.

Offline spy derman

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-2
Re: Gas Involving Experiment
« Reply #11 on: May 10, 2008, 09:56:49 AM »
has anyone finished their plan?

Sponsored Links