Hello Yggdrasil,
I have drawn out the molecular orbital diagrams for N2, N2+, Cl2, Cl2+
N2: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(π2py)2(π2pz)2(σ2px)2 0.112 nm
N2+: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(π2py)2(π2pz)2(σ2px)1 0.129 nm
Cl2: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(π2py)2(π2pz)2(σ2px)2(π2py*)2(σ2pz*)2 0.199 nm
Cl2+: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(π2py)2(π2pz)2(σ2px)2(π2py*)2(σ2pz*)1 0.189 nm
From this I can tell that N2+ will be longer because it has an unpaired electron in the (σ2px) orbital.
However Cl2, and Cl2+ are backwards reasoning.
Because I would think that Cl2+ would be longer (similar to N2+) because it has a lone electron in (σ2pz*) orbitals... however the length of the Cl2 bond is 0.199 nm where as the bond length in Cl2+ is 0.189 nm SHORTER.
How can my text book be right? How can that apply for bond length in N2 and N2+ but not Cl2 and Cl2+?
Can you suggest anything that would set me on the right path to understanding this?
Thank you for your help Yggdrasil!
New to Atoms