[henrii]

So i am trying to figure out how much silver i have in my mixture of silver nitrate
Is this how i do it

MW Ag/ MW AgNo3 x my mg of AgNo3/volume ( in mls)

This should give me the concentration in mg right? x by 1000 to give me g/L???


I am not 100 poercent sure if i have it right?

any help would be great


Henrii

[Borek]

Give more details about the mixture. Or do you mean solution?

[henrii]

wow that was a quick responce

well its a solution of Silver nitrate( 1mM) Citrate( 1mM) and Acid 1mM Nabh4)
i need to figure out how much silver is in it ( in theory) i will also experimentally check. but just not sure how to do this. Any help would be great


Thanks

Henrii

[Borek]

You are told - it contains 1 millimole of silver per liter of solution. That's definition.

Do you want to convert it to mass/liter? Just find the mass of 1 millimole of silver.

[henrii]

ah yes but this is where i get confused!

 I have 1mM of silver Nitrate, I just want to know how much silver is in the solution. So i was thinking it was calculated something like this -

MolWeight of  Ag / Mol Weight AgNo3 x  mg of AgNo3/volume ( in mls)

x by 1000 to give me g/L???

I am not sure if this is right however

for example using to get 1mM Silver nitrate in 200mls I weighed out 16.9mg
and using that technique above i come to the conclusion that i should have .053 (or 53.9mg/l??) but some how i think i am wrong because how can i have 53.9mg/l when i only started off with 16.9mg/l Silver nitate....


thanks for the reply.. hope u understand what i mean??

Henrii

[Borek]

i only started off with 16.9mg/l Silver nitate....

No, you started with 16.9mg/0.2L

[henrii]

Ah yes of course! So the way i calculated it is okay do you think?