[slu1986]

It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 25.0 C to 70.0 C.  What is the specific heat of benzene?

A) 1.10 J/ (g C)
B) 1.72 J/ (g C)<---------this is the answer that I got
C) 3.48 J/ (g C)
D) 5.41 J/ (g C)

This is how I worked it out:
q= (145 g) (70.0 - 25.0 C) C = 6525 g C

11.2 kJ * 1000 = 11200 J

11200 J / 6525 g C = 1.716 = 1.72 J/ (g C)

Did I do the problem right and come up with the right answer?

[DrCMS]

Looks good to me.