[selway]

Hello, I have a complicated pH question.  I have a 8 inch pipe that discharges 20,000 gallons/day and measurements of the pipe pH are 12.  If the volume was increased to 40,000 gallons/day with water with a pH of 8, what would the final pH be?

I am so confused.  I tried calculating moles of H+, but my volume is a rate, not an actual volume, so how do I change that to mol/liter?

AND, what if I just know the pH but not the chemical that is providing it?  

[Borek]

Forget about rates. Imagine you have collected all water in the poll and make your calculations on known volumes.

[AWK]

As a first aproximation, you can treat the problem, as dilution of water with pH=12  (twice). Forget about water with pH=8