[budman]

hey guys, i'm having trouble finding out h
ow to get mililitres from miligrams to complete a neutralizing problem, please help, with explanation

1. what volume of .350mol/L of potassium hydroxide is required to neutralize 0.200g of oxalic acid H2C2O4 - 2H20

please help

[jansenwrasse]

You can not go from mg to mL they are weight and volume measurements. 

Instead go backwords with the Molar solution to get grams(of solute).  Just be careful with this one, as you KOH has one OH- complex, and the H₂C₂O₄ + 2H₂O has 2 hydrogen molecules. (so you will need 2x as much KOH as if the solution had 1 - H)

From there just use Stoichiometry to fingure out the nutralizing ammounts.

[meenu]

titration equation is N1V1 = N2V2  (if normality is given)
 in case molarity is given then
look at the mole ratio in balanced equation
M1V1 acid / M2V2 base =Moles of acid in balanced equation / moles of base in balanced equation

here    mole ratio =acid / base = 1/2   
  2* M1V1 acid = M2V2 base

molarity * volume = no. of moles
here grams of acid is given
convert grams into moles
moles = weight in grams / molar mass = 0.200 / (126 g/mol) =0.00159

2* 0.00159 acid = 0.350 mol/litr * V  base
V= 0.0090 LITRE  = 9 ml

[jansenwrasse]

Well jeepers I didn't want to give him/her the answer