[gear2d]

I was wondering if anyone can help understand the ¹H NMR of this compound:
       Br     H
       |      |
CH3-C -   C-CH3
       |      |
       CH3  CH3
(sorry about the spacing, it was getting tight there)

I am not seeing how this is: a singlet, a doublet, and septet

[macman104]

The two CH3's on the left have no hydrogen on the connecting carbon, so they are not split at all.
The CH on the right has two CH3 (each with 3 hydrogens) groups connected, so n+1, makes that 6+1 = 7.
The two CH3's on the right have the one hydogen on the connecting carbon, so they are split into a doublet.