[susan__t]

I'm doing a pre-lab for a titration lab and the following question has been giving me a little grief:

KHP is a weak monoprotic acid, how many moles of NaOH are required to neutralize 0.616g of KHP?

I know that KHP is actually KHC₈H₄O₄ and calculated the amu to be 204g/mol and therefore that 0.616g is 0.00302 mol. 

That was all easy but what my question is, is that if the ratio of KHP to NaOH in the chemical is 1:1, does that mean that 0.00302 mol of NaOH are needed? 

[Astrokel]

hello,

yeeees you are right, the ratio is  1:1 because

KHP is a weak monoprotic acid

hope this helps some!!