November 23, 2024, 08:35:00 PM
Forum Rules: Read This Before Posting


Topic: Binary mixture - percent composition  (Read 5680 times)

0 Members and 1 Guest are viewing this topic.

Offline tiny101

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-1
Binary mixture - percent composition
« on: October 01, 2008, 07:13:25 PM »
Hello, I've hit a road block with this question and I'm hoping someone can point me in the right direction.

The problem states that a 5.30-g sample containing only Mn2(SO4)3(s) and Al2(SO4)3(s) is dissolved in aqueous solution. The metal ions are precipitated as hydroxides, which are pyrolyzed in air to produce 1.85 g of a mixture of Mn2O3(s) and Al2O3(s). What was the percent Mn in the original sample?

I've designated x = mass of Mn2O3 and with that, I found that the moles of Mn would be = 2x/157.87

What is the next step? Or, am I completely mistaken?
Thx in advance  ;D

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Binary mixture - percent composition
« Reply #1 on: October 02, 2008, 03:01:06 AM »
Assume x moles of manganese sulfate and y moles of aluminum sulfate. Write equations for mass of sulfates and mass of oxides (hint: use molar masses and stoichiometry). Two equations, two unknowns, simple algebra.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline tiny101

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-1
Re: Binary mixture - percent composition
« Reply #2 on: October 02, 2008, 08:37:45 PM »
How would I write the equation for the mass of oxides? Should I write up the chemical equations (as in how they react with one another) to figure out the moles of the oxides, then write the equation?

Thanks again.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27858
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Binary mixture - percent composition
« Reply #3 on: October 03, 2008, 04:18:19 AM »
Assume there are x moles of Mn.

What will be mass of the Mn2(SO4)3?

What will be mass of the Mn2O3?

These are very basic moles/mass conversions.

Now think - does the number of moles of Mx (x) change during the reactions, or not?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links