[soupastupid]

KOH is neutral right?

and so i have perchloric acid as being strong

and so the pH is

-log([HClO4])

and i get

pH = 1.086?

[Astrokel]

KOH is neutral?

[soupastupid]

HClO4 is a strong acid and completely dissociates
KOH is a strong base and completely dissociates

do i just take difference in pH i get to get pH?

so that means i get...

8.2×10^−2 M  HClO4 and 2.4×10^−2 M  KOH

pH = -log([HClO4])
pH = 1.086

pOH = -log([KOH])
pOH = 1.619
pH = 12.3

total pH = 13.47

right?

[enahs]

Neutralization of acid (or base)
OH^- + H⁺  H₂O

So, how much OH^- and H⁺ do you have?
Which one is in excess?
So now that you have an access of one, what is that excess? And thus what is that pH?

[soupastupid]

pH = 11.21  ?

[enahs]

How much perchloric acid do you start with? How much potassium hydroxide?
How much and of which one is left?

[Borek]

pH = 11.21  ?

Stop guessing and blindly throwing numbers around. This is a limiting reagent question. Calculate what is in excess, calculate concentration of excess subtance, that will give you pH.