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Topic: pH two component 3  (Read 4267 times)

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Offline soupastupid

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pH two component 3
« on: October 19, 2008, 03:35:38 PM »
im thinking

RbOH is neutral

because Rb is a alkali metal
and the charges cancel out

and so NaHCO3 has to be the sole pH contributor
the ka for HCO3 is

5.6*10^-11 (does this number seem too low)

Na is neutral
HCO3 is a weak base

but when i do
HCO3- + H2O <--> H2CO3 + OH-
i get pOH = 5.56
pH = 8.43

does that look right?

Offline Borek

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Re: pH two component 3
« Reply #1 on: October 19, 2008, 04:22:31 PM »
RbOH is neutral

because Rb is a alkali metal

Because Rb is alkali metal, RbOH is a strong base, just like NaOH.
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Offline soupastupid

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Re: pH two component 3
« Reply #2 on: October 19, 2008, 08:06:22 PM »
all alkali metals are strong bases when bonded with OH-?

so im think now...

RbOH is a strong base
and so
it completely dissociates into
RbOH --> Rb+ + OH-
and so i get
pOH = -log([RbOH])
pOH = 1.15
pH = 12.84

and i ignore NaHCO3 because it is a weak base?

Offline Borek

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Re: pH two component 3
« Reply #3 on: October 20, 2008, 02:54:53 AM »
all alkali metals are strong bases when bonded with OH-?

Yes.

Quote
and i ignore NaHCO3 because it is a weak base?

No. You don't ignore it. It is a weak acid as well. It will react with the strong base present in the solution. It is called neutralization reaction.

This is another limiting reagent question.
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