[sasan_f3000]

How do you get the initial concentration in Iodine Clock Reaction Experiment?
The concentration of KIO3 is 0.020 M.

The volume of KIO3 I used are: 1ml, 2ml, 3ml, 4ml, 5ml, 6ml, 7ml, 8ml, 9ml, 10ml

It says you need to calculate the initial concentration of potassium iodate for each of your dilutions. This is a simple dilution calculation where the initial concentration is the concentration of your stock solution (0.020M). Use the volume you used, determine the initial concentration by dividing by the total volume of 20.0 ml (volume of mixture).

I don't get it are we supposed to divide the volumes of 1ml, 2ml, 3ml, ect, by 20.0 ml?

[potatopotato]

No, no,

What you do is to find the final concentration of the solution...

In this case you need the formula c = n/v where
c = concentration (mol/L)
n = number of moles used.
v = volume of solution

Then you write this equation as n = cv
Then you compare the two values (initial and final)

in this case, c1v1 = c2v2
where c1v1 is the initial concentration and volume of KIO3, and final for the other.

Then you sub in the values you know like given initial concentration 0.020 M or 0.020 mol/L for c1.
You can sub in whatever initial value of KIO3 like 1ml, 2ml, 3ml, etc. for v1.

Then you sub in v2 as 20 ml since that is your final product solution
and then you solve for c2 and there you go, the concentration of potassium iodate for each of your dilutions.

Wow, this is a pretty tough lab you got, hope you get this before the lab is due..