In which compounds do the central atoms not obey the octet rule? (Enter all correct answers, i.e., B, AC, BCD...) A) H2S B) BH3 C) SiH4 D) OF2 E) XeOF4
Central atoms for each...
A)S, 16 electrons
B)B, 5 electrons
C)Si, 14 electrons
D)O, 8 electrons
E)XeO(?) (Not sure which is the central atom in this situation)
Thank you!
You misunderstand what the "octet rule"
is.
A key word in your question is
compound.
Basically, the octet “rule” is that atoms in compounds are “trying” to achieve “full outer shells” of electrons. The inverted commas indicate these phrases are significant simplifications.
For simple compounds the “octet rule” has quite wide applicability.
First, can you explain why NaCl satisfies the octet rule?
Can you explain why oxygen in water (H
2O) satisfies the octet rule and why “octet” has to be modified to explain the bonding of hydrogen?
Once you have that you can tackle the question.
Hint: This is a question about bonding and electrons. Where are the bonding electrons in the atoms in the compounds you have listed?
Clive