October 06, 2024, 09:27:48 AM
Forum Rules: Read This Before Posting


Topic: vinegar and soda in a sealed container  (Read 2782 times)

0 Members and 1 Guest are viewing this topic.

Offline hamil

  • Regular Member
  • ***
  • Posts: 34
  • Mole Snacks: +0/-0
vinegar and soda in a sealed container
« on: November 22, 2008, 09:15:30 PM »
mixing vinegar and soda produces CO2 among other items.  How can I calculate the pressure produced if I let the reaction proceed in a sealed container.  I can do the mole calculations but I know that some of the CO2 will dissolve in the water.  How does this dissolved gas affect the pressure?

Offline nj_bartel

  • Sr. Member
  • *****
  • Posts: 1487
  • Mole Snacks: +76/-42
Re: vinegar and soda in a sealed container
« Reply #1 on: November 22, 2008, 09:45:39 PM »
Think it out.  If you have a certain amount of gas enclosed in a chamber with liquid, and some of that gas is taken out of the gas phase by a liquid, will there be more or less gas in the bottle?  Does this translate to more or less pressure?  At any rate, the dissolved gas should be pretty negligible.  Oh, and don't blow yourself up.

Offline hamil

  • Regular Member
  • ***
  • Posts: 34
  • Mole Snacks: +0/-0
Re: vinegar and soda in a sealed container
« Reply #2 on: November 22, 2008, 10:18:11 PM »
I don't want to blow myself up.  I was hoping to get a reference of some sort that might relate the pressure of CO2 to the amount that would be disolved in a certain amount of water.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27806
  • Mole Snacks: +1808/-411
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: vinegar and soda in a sealed container
« Reply #3 on: November 23, 2008, 04:25:35 AM »
Henry's law.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links