[RJam]

A Pitot tube is used to determine the volumetric flowrate of a gas in a duct of circular cross section of diameter 1.5 m. A Pitot traverse using three data readings is used, presented in Table Q1. If the readings are taken at three radii that simplifies the calculation in which the centroids are of equal area, determine the position of the three readings expressed as r1/D, r2/D and r2/D, and the volumetric flowrate of the gas in the duct.
The volumetric flowrate, Q, is determined from
                       n
 Q= Aduct*1/n* ∑  * Vi
                       i=1
where Aduct is the duct cross sectional area, n is the number of points surveyed and vi is the indicated velocity at each measurement point.

Table Q1

Position               r1/D   r2/D   r3/D
Diff Pressure (Pa)    441   529   576

The density of the gas may be taken as 2.0 kg.m-3.

State any assumptions.

Any help would be brilliant. Its a pretty standard Pitot traverse I think I just cant set out the calculation properly

Thanks