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Topic: molarity problem  (Read 4121 times)

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Offline itsme03

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molarity problem
« on: December 06, 2008, 09:19:12 PM »
a 200.0 mL sample of H3PO3 requires 22.50mL of 0.1250 M NaOH for the complete neutralization. what is the molarity of the H3PO3 solution?

the balanced equation is H3PO3 + 2NaOH  :rarrow: 2H2O + Na2H3PO3

i tried just about everything, but the closest i got was .28 M
the answers .007 M

Offline Astrokel

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Re: molarity problem
« Reply #1 on: December 06, 2008, 10:30:22 PM »
Check your product chemical formula again!
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline itsme03

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Re: molarity problem
« Reply #2 on: December 06, 2008, 11:14:23 PM »
i did. its right.

Offline Bioionic

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Re: molarity problem
« Reply #3 on: December 07, 2008, 12:14:50 AM »
No, in your product should be a salt.

Offline itsme03

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Re: molarity problem
« Reply #4 on: December 07, 2008, 01:47:12 AM »
i checked and that's what the book said the product's supposed to be. how do you know there should be a salt?

Offline Astrokel

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Re: molarity problem
« Reply #5 on: December 07, 2008, 01:56:04 AM »
Generally an acid-base reaction gives salt and water or just salt. In acid-base reaction, the underlying reaction should be H+ from the acid reacting with OH- from the base to give water.

Quote
Na2H3PO3
This is wrong because complete neutralization means all the acidic hydrogen from your acid have reacted to become water, all it left in product should be just the anion.
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline Bioionic

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Re: molarity problem
« Reply #6 on: December 07, 2008, 02:40:59 AM »
Also remember the double replacement reaction.

AB + XY ---> AY + XB

Offline itsme03

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Re: molarity problem
« Reply #7 on: December 07, 2008, 07:05:21 PM »
got it. thanks

Offline Bioionic

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Re: molarity problem
« Reply #8 on: December 08, 2008, 02:29:35 AM »
Well... For other peeps that may be struggling with a similar problem.  Do you care to share your solution?  I always like to hear how someone else solves a problem.

I guess you did see the error in your original eq.

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