[ARGOS++]

Dear miguel_91;

The Diagram/Scheme would results in:

   B.)  :            3Fe(OH)₂     +     2H₃PO₄  --->   1Fe₃(PO₄)₂   +   6H₂O
   C₁.) :          89.85 g/mole          98.0 g/mole
   C_m.):             3.2 g                   2.5 g
   C₂.) :          0.03561 mole        0.02551 mole
   D.)  :          0.01187               0.01275

And now which is the limiting reagent (the lower multiplier on D.))?

You see that with the Diagram on: "Stoichiometry Problem” it can be such easy!
Good Luck!
                    ARGOS⁺⁺