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Topic: How much oxygen is produced by the decomposition of 6.54 g of KClO3 ?  (Read 6382 times)

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Offline jacquelinehang

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How much oxygen is produced by the decomposition of 6.54 g of KClO3 ?
« on: January 14, 2009, 09:11:03 PM »
How many molecules of oxygen are produced by the decomposition of 6.54 g of potassium chlorate (KClO3)? 2KClO3 (s) -----> 2KCl(s) + 3O2(g)

I don't understand this question. Can someone PLEASE tell me the correct way to do it? Don't just give me the answer! Thanks.
« Last Edit: January 27, 2009, 06:33:23 AM by geodome »
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Offline Mitch

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Re: This has been driving me CRAZY!!!!
« Reply #1 on: January 14, 2009, 11:08:47 PM »
It looks like your equation is balanced. Start by figuring out how many moles of of KClO3 you have. Do you remember how to do that?
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