[elliotyang]

Given solubility of Ba(NO₃)₂ is
34g/100 H²0 at 100^oC
5g/100g of H²0 AT 0^oC
if one starts with 100g of BaNO₃)₂ and make a saturated solution in water at 100^oC, and then cooled to 0^oC, how much NO₃)₂ is crystallised out of solution?
The resultant crystals carry along with them on surface 4g of H²0 per 100g of the crystals.

Initial the concentrated solution would be 100g/300g H²0 if i do not calculate wrongly.
then how should i proceed?
 

[ARGOS++]

[elliotyang]

The difference is crystallised and you have to correct this difference for four crystal-water.

What difference are you referring to? The difference between the solubility at the different temperature?

If it is correct, then the amount of is not crystallized will be 5.0g*294.1g/100g H₂O=14.71/294.1 H₂O 
Am I correct?

[ARGOS++]

Dear elliotyang;

Correct!, -  for how much is NOT crystallised!

Now how much is crystallised and how much water is left on its surface?

Good Luck!
                    ARGOS⁺⁺