Topic: phase change practice with other variables (Read 25230 times)

ARGOS++ · « **Reply #30 on:** February 05, 2009, 05:59:31 PM »

Dear reezyfbaby;

Bravo!, - You did it!

Please think once again how we did it!

For your new Question: You mixed Joules up with calories!

Good Luck!
ARGOS⁺⁺

mr cool · « **Reply #31 on:** February 05, 2009, 06:03:20 PM »

Quote from: ARGOS++ on February 05, 2009, 05:59:31 PM

Dear reezyfbaby;

Bravo!, - You did it!

Please think once again how we did it!

For your new Question: You mixed Joules up with calories!

Good Luck!
ARGOS⁺⁺

where did i mix them up? i don't see joules anywhere in that problem.

ARGOS++ · « **Reply #32 on:** February 05, 2009, 06:07:07 PM »

Dear reezyfbaby;

Can you identify: 59.75 J in your question/problem? J stands for Joules!

Good Luck!
ARGOS⁺⁺

mr cool · « **Reply #33 on:** February 05, 2009, 06:08:22 PM »

Quote from: ARGOS++ on February 05, 2009, 06:07:07 PM

Dear reezyfbaby;

Can you identify: 59.75 J in your question/problem? J stands for Joules!

Good Luck!
ARGOS⁺⁺

yea but i converted 59.75 joules into 250 calories. i know that J stands for Joules.

ARGOS++ · « **Reply #34 on:** February 05, 2009, 06:11:43 PM »

Dear reezyfbaby;

Remember!: For that you have to divide it, - not multiply!

Good Luck!
ARGOS⁺⁺

mr cool · « **Reply #35 on:** February 05, 2009, 06:20:25 PM »

Quote from: ARGOS++ on February 05, 2009, 06:11:43 PM

Dear reezyfbaby;

Remember!: For that you have to divide it, - not multiply!

Good Luck!
ARGOS⁺⁺

oh, that would explain it lol

so this is my first step?
(.5 cal/g)(50.00g)(F - -10.00*C) = 14.28 cal?

ARGOS++ · « **Reply #36 on:** February 05, 2009, 06:25:08 PM »

mr cool · « **Reply #37 on:** February 05, 2009, 06:37:17 PM »

ARGOS++ · « **Reply #38 on:** February 05, 2009, 06:43:29 PM »

mr cool · « **Reply #39 on:** February 05, 2009, 06:49:20 PM »

ARGOS++ · « **Reply #40 on:** February 05, 2009, 06:56:38 PM »

mr cool · « **Reply #41 on:** February 05, 2009, 07:04:42 PM »

w/e i gave up on that problem because it frustrated me and i started the last one....

26.46 KJ of energy is released from 10.00 grams of steam as it condenses from 125.00*C. What is the final temerature of the condensed water?

(.5 cal/g *C)(10.00g)(100-125) + (-540 cal/g)(10.00g)+(1.0 cal/g)(10.00g)(F-100*C) = 6323 calories

-125 cal + 5400 cal + 10 cal/g(F-100*C)=6323 calories

(10.00 cal/g)(F^o - 100*C) = 1038 calories

10.00 cal/g F^o

1038 calories
------------- = 103.8 *C
10.00 cal/g F^o

ARGOS++ · « **Reply #42 on:** February 05, 2009, 07:12:30 PM »

mr cool · « **Reply #43 on:** February 05, 2009, 07:17:07 PM »

Topic: phase change practice with other variables (Read 25230 times)

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

ARGOS++

Re: phase change practice with other variables

mr cool

Re: phase change practice with other variables

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