[jnimagine]

a 1.00 steel bulb containing a fixed amount of CO2 gas at a pressure of 1atm and a 2.00L steel bul containing a fixed amount of Ne gas at 5.00atm are connected to each other by a closed valve.  What will be the final pressure in the 2.00L bulb when the valve is opened? Assume that both gases behave ideally and that the temperature of both bulbs are the same throughout the process.

I'm having a hard time trying to figure this question out...
stuck on applying the condition 'when the valve is opened'. = =
please *delete me*!

Thank you!

[Astrokel]

It just means the gas are allowed to mix.

[jnimagine]

It just means the gas are allowed to mix.

then how would you apply the gas law here?
do i just add the two substances together? so like p1v1 + p2v2?
but the question only asks for volume of one of the bulb...:S

[ARGOS++]

Dear jnimagine;

Sorry, not the final volume is asked, but the final pressure!

p1v1 + p2v2 is ok for the left side of the equation.  So what will be on the right side of the equal sign?

Good Luck!
                    ARGOS⁺⁺

[jnimagine]

Dear jnimagine;

Sorry, not the final volume is asked, but the final pressure!

p1v1 + p2v2 is ok for the left side of the equation.  So what will be on the right side of the equal sign?

Good Luck!
                    ARGOS⁺⁺

when the valve is opened, is the pressure in the two bulbs same?
then
p1v1 + p2v2 = ptotvtot?
do you add the two volumes for v total??!?!?

[ARGOS++]

Dear jnimagine;

Correct!, -  three times.
(When open - then the pressure must be the same!  Otherwise what?)

Good Luck!
                    ARGOS⁺⁺