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Topic: Isopropanol in a breathalyser  (Read 5827 times)

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Offline MightyMan

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Isopropanol in a breathalyser
« on: February 04, 2009, 03:29:29 PM »
Hey guys,
i need some help with this question:

Quote
If a person drank rubbing alcohol (isopropanol), a breathalyser analysis (in units of mg/100 mL blood) would be in error.  Its reading would be:
1. Too high by a factor of 1.3
2. Too low by a factor of 1.3
3. Too high by a factor in 2.6
4. Too low by a factor of 2.6

my professor skimmed over how ethanol is detected in a breathalyser from a colour change of a cromate compound, but i'm not too sure how this relates to isopropanol.
I also know that in the reaction of the cromate colour change, ethanol is oxidized into acetic acid, however isopropanol would oxidized into a ketone, but im not sure how to connect it to the question.

Thanks in advanced.

Offline Dan

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Re: Isopropanol in a breathalyser
« Reply #1 on: February 06, 2009, 06:31:56 AM »
OK, a breathalyser works by the chromate oxidation of the alcohol which gives a colour change.

Fist of all, what would the oxidation products of ethanol and isopropanol be?
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Offline MightyMan

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Re: Isopropanol in a breathalyser
« Reply #2 on: February 06, 2009, 08:33:38 AM »
The oxidation products for ethanol and isopropanol would be acetic acid and propanone, respectively.

I thought of finding a ratio between the molecular weights of ethanol and isopropanol, and that got me to 1.3, but i dont know if its too high or too low by that factor.
Plus i'd like to understand why...

Offline sjb

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Re: Isopropanol in a breathalyser
« Reply #3 on: February 06, 2009, 08:53:30 AM »
That's a start, now can you write balanced equations for each of the oxidations?

S

Offline MightyMan

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Re: Isopropanol in a breathalyser
« Reply #4 on: February 06, 2009, 01:55:49 PM »
2 K2Cr2O7+ 3 C2H5OH + 8 H2SO4 -> 2 K2SO4+ 2 Cr2(SO4)3+ 3 CH3COOH + 11 H2O
would be the ethanol (this was provided for me in my lecture notes)

using the equation and replacing ethanol for isopropanol and acetic acid for acetone, i got:
K2Cr2O7 + 3 C3H7OH + 4 H2SO4 -> K2SO4 + Cr2(SO4)3 + 3 C3H6O + 7 H2O

therefore since Cr2(SO4)3 is the colour change and there is 1 more mole of it in the ethanol reaction, would isopropanol would give an error in reading 1.3 (ratio of molecular weights) lower

Does that sound right?

Offline sjb

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Re: Isopropanol in a breathalyser
« Reply #5 on: February 11, 2009, 11:42:46 AM »
The amount of dichromate is fixed in the breathalyser, so taking this into account, you effectively have the equations

2 K2Cr2O7+ 3 C2H5OH + 8 H2SO4  :rarrow: 2 K2SO4 + 2 Cr2(SO4)3+ 3 CH3COOH + 11 H2O for ethanol.

and

2 K2Cr2O7 + 6 C3H7OH + 8 H2SO4  :rarrow: 2 K2SO4 + 2 Cr2(SO4)3 + 6 C3H6O + 7 H2O for IPA.

so what is the ratio by weight of EtOH : 2  IPA ?

S

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