I think I'm making a silly mistake somewhere along my calculations, since I'm not sure why I'm off by about 300 joules, but anyway.
Calculate the total heat (in J) needed to convert 22.00 g of ice at -6.00 C to liquid water at 0.500 CGiven: mp at 1atm = 0.0 C
:delta: H
fus = 6.02 kJ/mol = 6020 J/mol
C
liquid= 4.21 J/g*C
C
solid=2.09 J/g*C
SOOO, I first calculate the energy by
H
2O (s) [-6.00C]
H
2O (s) [0.00C]
q=nC
H2O Solid :delta: T
q=(22.00gH
2O x 1 mol H
2O/ 17.02 g)(2.09 J/g*C)(0.00 C - -6.00 C)
q=15.29 J
Then,
H
2O (s) [0.00 C]
H
2O (l) [0.00 C]
q=n(:delta: H
fus)
q=1.22 (6.02 kJ/mol x 10
3J /1 kJ)
q=7344 J
Next,
H
2O (l) [0.00 C]
H
2O (l) [0.500]
q=nC
H2O liquid :delta: T
q=(22.00gH
2O x 1 mol H
2O/ 17.02 g)(4.21 J/g*C)(0.500 - 0.00)
q=2.56 J
Finally,
Q
total = 2.56 J +7344 J + 15.29 J = 7361.85 J
But the BOOK SAYS 7670 J
What the heck?!
Any help is appreciated I spent so much time on the formatting alone haha, it might be an arithmetic error or a conceptual error.