I'm having some trouble solving this problem. I was wondering if someone could give me some guidance?
"A gas containing equal parts of methane, ethane, and ammonia flows at a constant rate through a laboratory water-based absorption unit, which absorbs 96% of the ammonia and retains it in the liquid. No methane or ethane is absorbed into the water and no water evaporates into the gas. Initially, there was exactly 5.00 kg of water in the absorber, and at the end of 4 hours of operation, the liquid mass is 5.25 kg. Calculate the molar flow rate (mol/hr) of the gas stream coming into the absorber, and the mole fraction of ammonia in the exit gas stream."
Here is what I have tried:
To calculate the molar flow rate, I subtracted 5.00kg from 5.25kg, which gives .25 kg. I assumed this .25kg to be ammonia, based on the information in the problem. I then divided .25 by 4 hours, which gives .0625 kg/hr. I then converted .0625 kg ammonia to moles of ammonia, but I did not get the correct answer. The answer for the first part is supposed to be 11.48 moles/hr.
I'm not even sure how to start answering the second part of the question.
Any help would be much appreciated.