[clearsights]

Ok, We just started this in class and I have no idea how to do it.

When calcium carbonate reacts with hydrochloric acid, the products are carbon dioxide, water and calcium chloride. What volume of carbon dioxide at 785 torr and 27.0 degrees C is produced when an excess of calcium carbonate is added to 10.0 L of 0.158 M hydrochloric acid.

Any help would be appreciated!

[sjb]

So the reaction is CaCO₃ + HCl  CaCl₂ + H₂O + CO₂.

Can you balance this, and then based on your limiting reactant find how much carbon dioxide is released?

S

[leve]

CaCO3 + 2HCl → CO2 + H2O + CaCl2

Give that CaCO3 is in excess so don't worry about limiting reagent.

Use 10.0 L of 0.158 M hydrochloric acid to find moles of HCl.

Use the moles of HCl to find how many moles of CO2 is needed by stoichiometry

Use PV=nRT to find volume of CO2 needed with given that it is at 785 torr and 27.0 degrees C and n is the number of moles needed.