Consider the dissolution of the compound X2Y3, which gives X2Y22+, X2Y4+, X2Y3(aq), and Y2-. Use the mass balance to find an expression for [Y2-] in terms of the other concentrations. Simplify your answer as much as possible.
This is just a problem I'm doing for practice, so I have the answer, but I don't follow it.
Y total = (3/2)(X total)
I understand this. But the next step I do not follow:
2[X2Y22+] + [X2Y4+] + 3[X2Y3] + [Y2-] = 3/2{2[X2Y22+] + 2[X2Y4+] + 2[X2Y3]}
Where did all the coefficients of 2 and 3 come from??
Final Answer
[Y2-] = [X2Y22+] + 2[X2Y4+]