Topic: Redox equation (Read 5459 times)

escapeartistq · « **on:** May 18, 2005, 07:06:56 PM »

I am having a hard time understanding this redox equation.

Hg₂Cl₂ -> Hg₂²⁺ + 2Cl^-

What are the oxidation numbers for all the elements in this equation?

Nano · « **Reply #1 on:** May 18, 2005, 07:15:55 PM »

Hg2Cl2 -> Hg22+ + 2Cl-
+1 ,-1--> 2+ , -1

sorry, I am not sure if it's right

Borek · « **Reply #2 on:** May 18, 2005, 07:28:09 PM »

Quote from: escapeartistq on May 18, 2005, 07:06:56 PM

I am having a hard time understanding this redox equation.

There is no redox reaction here, this is simple dissociation. Both Hg in Hg2(2+) can be trated as +1.

escapeartistq · « **Reply #3 on:** May 18, 2005, 08:05:59 PM »

But here http://www.qivx.com/ispt/elements/ptw_080.php it says it is a redox equation. Also, I took the equation from a chemistry problem in which you have to identify dismutations among a number of given equations, and this was one them. The solution to the problem says this is not a dismutation but I don't understand how it is a redox equation either.

AWK · « **Reply #4 on:** May 19, 2005, 01:15:07 AM »

But this link shows this reaction:
Hg2Cl2 + 2e- => 2Hg + 2Cl-
reduction

Topic: Redox equation (Read 5459 times)

escapeartistq

Redox equation

Nano

Re:Redox equation

Borek

Re:Redox equation

escapeartistq

Re:Redox equation

AWK

Re:Redox equation

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